OK I remember it now. Here is how you do it.
[3 + (2a + b)]˛
first take out the brackets and the ˛ means multiply it by itself so
(3 + 2a + b)(3 + 2a + b)
Now you jump the multiplications, first take the first 3 and distribute it into each thing in the second parentheses then do the same with the 2a and b so
(3*3) + (3*2a) + (3*b) + (2a*3) + (2a*2a) + (2a*b) + (b*3) + (b*2a) + (b*b)
=
9 + 6a + 3b + 6a + 4a˛ + 2ab + 3b + 2ab + b˛
then combine like terms
9 + 12a + 6b + 4a˛ +4ab + b˛
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Re: What the book says (and I still don't understand at all)
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Re: Algebra help!
