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Jdurgi
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Reged: 09/21/03
Posts: 1009
Loc: NEW England, CT
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Re: Just started College Algebra
03/18/13 08:11 AM


> > If you're telling me that X^-Nth = 1/X^Nth, then the reverse must be true and it
> sure
> > as hell is not! You can actually calculate a real number for 1/X^Nth.
>
> The reverse is true? 8^(-2) = 1/64 = 0.015625 positive exponent is how many times you
> multiply by a number. Negative exponent is how many times you divide by a number. (8
> * 8 or 8 /
>
> What is really going to bake your noodle is the square root of -1. (BOOM! Headshot.)

Don't forget the fact that the value 0.999... is mathematically equivalent to 1. (Collapses and dies).


--------------------------------------------------
I am just a worthless liar.
I am just an imbecile.
I will only complicate you.
Trust in me and fall as well.








Entire thread
Subject Posted by Posted on
* Just started College Algebra URherenow 03/17/13 06:16 PM
. * Re: Just started College Algebra italieAdministrator  03/18/13 03:45 AM
. * Re: Just started College Algebra Olivier Galibert  03/20/13 02:29 PM
. * Re: Just started College Algebra italieAdministrator  03/21/13 02:35 AM
. * Re: Just started College Algebra StilettoAdministrator  03/21/13 07:39 AM
. * Re: Just started College Algebra italieAdministrator  03/25/13 08:21 PM
. * Re: Just started College Algebra Olivier Galibert  03/21/13 11:54 AM
. * Re: Just started College Algebra StilettoAdministrator  03/20/13 03:41 PM
. * Re: Just started College Algebra URherenow  03/18/13 07:14 AM
. * Re: Just started College Algebra TriggerFin  03/18/13 04:18 PM
. * Re: Just started College Algebra amused  03/18/13 02:49 PM
. * Re: Just started College Algebra URherenow  03/18/13 03:53 PM
. * It *is* compound interest -nt- amused  03/20/13 05:12 PM
. * Re: Just started College Algebra italieAdministrator  03/18/13 08:05 AM
. * 8[i][/i]) Tomu Breidah  03/18/13 09:51 AM
. * Huh? URherenow  03/18/13 03:55 PM
. * Re: Huh? Tomu Breidah  03/18/13 05:30 PM
. * Re: Just started College Algebra Jdurgi  03/18/13 08:11 AM
. * (e^(i*π)) + 1 = 0 *nt* StilettoAdministrator  03/18/13 08:45 AM
. * Re: (e^(i*π)) + 1 = 0 *nt* Vas Crabb  03/18/13 06:59 PM
. * I don't care how much epi you're doing, any amount of pie is always greater (nt) TriggerFin  03/18/13 09:11 PM

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